![]() ![]() We can also configure sudo usage without any passwords by tweaking this file. You can grant additional permissions to regular users by adding them to the sudoers list. Configure sudo Without Password The sudoers file in Linux allows admins to manage usage rights for different users. So a bit of experimentation will be needed -). Luckily, you can easily use the sudo command without passwords. So I suspect is a matter of finding all the occurences of pam_unix.so in the files above, and add the option nullok (or change the nullok_secure to nullok) to the entries.Īccording to this post the file should be /etc/pam.d/common-auth - but I am not sure about this because in Ubuntu the VC are in the /etc/securetty list so the null password for root should work from there (although not from a terminal emulator), and the SO states it doesn't work. Set to one of the values found in /etc/securetty. Password to access the service as long as the value of PAM_TTY is To a service if their official password is blank. The nullokĪrgument overrides this default and allows any user with a blank The default action of this module is to not permit the user access Now you will be able to use sudo when logged in under your normal user ID. Now, the module that check for the passwords "unix style" is pam_unix.so, in which man page you can find among the options: nullok To enable sudo for your user ID on RHEL, add your user ID to the wheel group: Become root by running su. So, sudo poweroff will now result in a passwordless shutdown. ![]() In /etc/pam.d there are all the PAM configuration files that tell the system how to do the authentication of users. This allows the user/group to run the above three commands, using sudo, however with no password. I want to add a user to Red Hat Linux that will not use a password for logging in, but instead use a public key for ssh. I think this is a PAM thing (PAM= pluggable authentication modules). Warning not tested because I think it's not such a great idea, even for a VM (bad habits are difficult to remove.). ![]()
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